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x^2-50x=500
We move all terms to the left:
x^2-50x-(500)=0
a = 1; b = -50; c = -500;
Δ = b2-4ac
Δ = -502-4·1·(-500)
Δ = 4500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4500}=\sqrt{900*5}=\sqrt{900}*\sqrt{5}=30\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-30\sqrt{5}}{2*1}=\frac{50-30\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+30\sqrt{5}}{2*1}=\frac{50+30\sqrt{5}}{2} $
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